Course Content
Chapter 1 Real Numbers
0/2
Chapter 2 Polynomials
0/2
Chapter 3 Pair OF Linear Equations
0/3
Chapter 4 Quadratic Equations
0/3
Chapter 5 Arithmetic Progressions
0/3
Chapter 7 Coordinate Geometry
0/2
Chapter 8 Introduction to Trigonometry
0/4
Chapter 9 Applications Of Trigonometry
0/1
Chapter 10 Circles
0/2
Chapter 11 Areas related to circles
0/1
Chapter 12 Surface Area & Volumes
0/2
Chapter 14 Probability
0/1
10th Maths NCERT Course
About Lesson

Exercise 8.2

1. Evaluate the following:

(i) sin 60° cos 30° + sin 30° cos 60°

(ii) 2 tan2 45° + cos2 30° – sin2 60

solution: 

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Ncert solutions class 10 chapter 8-4

solution: 

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solution: 

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solution: 

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2. Choose the correct option and justify your choice :
(i) 2tan 30°/1+tan230° =
(A) sin 60°            (B) cos 60°          (C) tan 60°            (D) sin 30°
(ii) 1-tan245°/1+tan245° =
(A) tan 90°            (B) 1                    (C) sin 45°            (D) 0

solution: 

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(iii)  sin 2A = 2 sin A is true when A =
(A) 0°                   (B) 30°                  (C) 45°                 (D) 60°

(iv) 2tan30°/1-tan230° =
(A) cos 60°          (B) sin 60°             (C) tan 60°           (D) sin 30°

solution: 

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3. If tan (A + B) = √3 and tan (A – B) = 1/√3 ,0° < A + B ≤ 90°; A > B, find A and B

solution: 

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4. State whether the following are true or false. Justify your answer.

(i) sin (A + B) = sin A + sin B.

(ii) The value of sin θ increases as θ increases.

(iii) The value of cos θ increases as θ increases.

(iv) sin θ = cos θ for all values of θ.

(v) cot A is not defined for A = 0°.

solution: 

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